Function matchpairs does not work in MATLAB R2023a when I use a sparse cost matrix. Please help me out ASAP!
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You can run this simple code and see my problem. Am I doing something wrong?
% testing matchpairs ----------------------------------------------------------------
clear;clc
% --- using matrix in usual form (not sparse) --- WORKS
M = 99*ones(16,16);
M(1,1) = 2;
M(2,1) = 1;
M(1,2) = 1;
M(3,2) = 2;
M(2,3) = 2;
M(4,3) = 1;
M(6,3) = 4;
M(3,4) = 1;
M(4,4) = 2;
M(7,4) = 4;
M(6,5) = 2;
M(8,5) = 1;
M(3,6) = 4;
M(5,6) = 2;
M(7,6) = 1;
M(4,7) = 4;
M(6,7) = 1;
M(10,7) = 2;
M(5,8) = 1;
M(9,8) = 2;
M(8,9) = 2;
M(12,9) = 1;
M(7,10) = 2;
M(11,10) = 1;
M(13,10) = 4;
M(10,11) = 1;
M(12,11) = 2;
M(14,11) = 4;
M(9,12) = 1;
M(11,12) = 2;
M(10,13) = 4;
M(13,13) = 2;
M(14,13) = 1;
M(11,14) = 4;
M(13,14) = 1;
M(15,14) = 2;
M(14,15) = 2;
M(16,15) = 1;
M(15,16) = 1;
M(16,16) = 2;
[matchings, unassignedRows, unassignedCols] = matchpairs(M,12345)
OUTPUT IS CORRECT:
% --- using sparse matrix --- DOES NOT WORK
Ms = sparse(16,16);
Ms(1,1) = 2;
Ms(2,1) = 1;
Ms(1,2) = 1;
Ms(3,2) = 2;
Ms(2,3) = 2;
Ms(4,3) = 1;
Ms(6,3) = 4;
Ms(3,4) = 1;
Ms(4,4) = 2;
Ms(7,4) = 4;
Ms(6,5) = 2;
Ms(8,5) = 1;
Ms(3,6) = 4;
Ms(5,6) = 2;
Ms(7,6) = 1;
Ms(4,7) = 4;
Ms(6,7) = 1;
Ms(10,7) = 2;
Ms(5,8) = 1;
Ms(9,8) = 2;
Ms(8,9) = 2;
Ms(12,9) = 1;
Ms(7,10) = 2;
Ms(11,10) = 1;
Ms(13,10) = 4;
Ms(10,11) = 1;
Ms(12,11) = 2;
Ms(14,11) = 4;
Ms(9,12) = 1;
Ms(11,12) = 2;
Ms(10,13) = 4;
Ms(13,13) = 2;
Ms(14,13) = 1;
Ms(11,14) = 4;
Ms(13,14) = 1;
Ms(15,14) = 2;
Ms(14,15) = 2;
Ms(16,15) = 1;
Ms(15,16) = 1;
Ms(16,16) = 2;
[matchings, unassignedRows, unassignedCols] = matchpairs(Ms,-1)
0 Commenti
Risposta accettata
Ulyana Grechaniuk
il 10 Apr 2024 alle 20:57
1 Commento
Bruno Luong
il 11 Apr 2024 alle 15:54
Modificato: Bruno Luong
il 11 Apr 2024 alle 15:56
@Ulyana Grechaniuk you are welcome.
You should move your reply to comment using the cross arrows "Move" on the top right. Thanks.
Più risposte (1)
Bruno Luong
il 9 Apr 2024 alle 7:04
Modificato: Bruno Luong
il 9 Apr 2024 alle 8:46
Your sparse matrix filled default cost wit 0 not 99. Then your expectation on that the result is identocal for different cost matrices (regardless data structure using) is simply plain wrong.
If you fill sparse or dense matrix with the same values it give identical outputs:
% testing matchpairs ----------------------------------------------------------------
clear;clc
% --- using matrix in usual form (not sparse) --- WORKS
M = 99*ones(16,16);
M(1,1) = 2;
M(2,1) = 1;
M(1,2) = 1;
M(3,2) = 2;
M(2,3) = 2;
M(4,3) = 1;
M(6,3) = 4;
M(3,4) = 1;
M(4,4) = 2;
M(7,4) = 4;
M(6,5) = 2;
M(8,5) = 1;
M(3,6) = 4;
M(5,6) = 2;
M(7,6) = 1;
M(4,7) = 4;
M(6,7) = 1;
M(10,7) = 2;
M(5,8) = 1;
M(9,8) = 2;
M(8,9) = 2;
M(12,9) = 1;
M(7,10) = 2;
M(11,10) = 1;
M(13,10) = 4;
M(10,11) = 1;
M(12,11) = 2;
M(14,11) = 4;
M(9,12) = 1;
M(11,12) = 2;
M(10,13) = 4;
M(13,13) = 2;
M(14,13) = 1;
M(11,14) = 4;
M(13,14) = 1;
M(15,14) = 2;
M(14,15) = 2;
M(16,15) = 1;
M(15,16) = 1;
M(16,16) = 2;
[matchings, unassignedRows, unassignedCols] = matchpairs(M,12345)
matchings
Ms = sparse(M);
[matchings, unassignedRows, unassignedCols] = matchpairs(M,12345);
matchings
Cross check, now both filled with 0s
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
% --- using sparse matrix --- DOES NOT WORK
Ms = sparse(16,16);
Ms(1,1) = 2;
Ms(2,1) = 1;
Ms(1,2) = 1;
Ms(3,2) = 2;
Ms(2,3) = 2;
Ms(4,3) = 1;
Ms(6,3) = 4;
Ms(3,4) = 1;
Ms(4,4) = 2;
Ms(7,4) = 4;
Ms(6,5) = 2;
Ms(8,5) = 1;
Ms(3,6) = 4;
Ms(5,6) = 2;
Ms(7,6) = 1;
Ms(4,7) = 4;
Ms(6,7) = 1;
Ms(10,7) = 2;
Ms(5,8) = 1;
Ms(9,8) = 2;
Ms(8,9) = 2;
Ms(12,9) = 1;
Ms(7,10) = 2;
Ms(11,10) = 1;
Ms(13,10) = 4;
Ms(10,11) = 1;
Ms(12,11) = 2;
Ms(14,11) = 4;
Ms(9,12) = 1;
Ms(11,12) = 2;
Ms(10,13) = 4;
Ms(13,13) = 2;
Ms(14,13) = 1;
Ms(11,14) = 4;
Ms(13,14) = 1;
Ms(15,14) = 2;
Ms(14,15) = 2;
Ms(16,15) = 1;
Ms(15,16) = 1;
Ms(16,16) = 2;
[matchings, unassignedRows, unassignedCols] = matchpairs(Ms,-1);
matchings
Mf = full(Ms);
[matchings, unassignedRows, unassignedCols] = matchpairs(Mf,-1);
matchings
1 Commento
Bruno Luong
il 9 Apr 2024 alle 7:17
One way to use sparse and keep filling 0 is to shift the value of the cost matrix
% testing matchpairs ----------------------------------------------------------------
Ms = sparse(16,16);
Ms(1,1) = 2;
Ms(2,1) = 1;
Ms(1,2) = 1;
Ms(3,2) = 2;
Ms(2,3) = 2;
Ms(4,3) = 1;
Ms(6,3) = 4;
Ms(3,4) = 1;
Ms(4,4) = 2;
Ms(7,4) = 4;
Ms(6,5) = 2;
Ms(8,5) = 1;
Ms(3,6) = 4;
Ms(5,6) = 2;
Ms(7,6) = 1;
Ms(4,7) = 4;
Ms(6,7) = 1;
Ms(10,7) = 2;
Ms(5,8) = 1;
Ms(9,8) = 2;
Ms(8,9) = 2;
Ms(12,9) = 1;
Ms(7,10) = 2;
Ms(11,10) = 1;
Ms(13,10) = 4;
Ms(10,11) = 1;
Ms(12,11) = 2;
Ms(14,11) = 4;
Ms(9,12) = 1;
Ms(11,12) = 2;
Ms(10,13) = 4;
Ms(13,13) = 2;
Ms(14,13) = 1;
Ms(11,14) = 4;
Ms(13,14) = 1;
Ms(15,14) = 2;
Ms(14,15) = 2;
Ms(16,15) = 1;
Ms(15,16) = 1;
Ms(16,16) = 2;
% Shift matrix
[I,J,K] = find(Ms);
fillvalue = 99;
Msshift = sparse(I,J,K-fillvalue,16,16);
[matchings, unassignedRows, unassignedCols] = matchpairs(Msshift,12345);
matchings
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