Need help in stepwise function

3 visualizzazioni (ultimi 30 giorni)
sagar pokhrel
sagar pokhrel il 16 Set 2014
Commentato: Saagar il 17 Set 2014
r=[0.5,1,1.5....5]; theta= linspace(0,2*pi,73); [theta,r]=meshgrid(theta,r); [x11,y11]=pol2cart(theta,r); x1= x11(:);
% I have a function z whose input needs to be x and y between [-1,1] so I need to change x and y both %such that for x1>1, x=1, x1<-1, x=-1 and -1<=x1<=1, x=x1 % i tried this for k=1:length(x1) if x1(k)<-1 x(k)=-1 else if x1(k)>=-1 && x1(k)<= 1 x(k)=x1 else if x1(k)>1 x(k)=1 end end
z= 1.3249-.004937*x+5.43243*x.^2-1.153*x.*3+4.2693*y.^6 % Repeating same for Y as well. when I run this i get In an assignment A(I)=B and I must be same. Is anyone able to help me. Thanks in advance

Accedi per rispondere a questa domanda.

Risposta accettata

Saagar
Saagar il 16 Set 2014
for k=1:length(x1)
if x1(k)<-1
x(k)=-1
elseif x1(k)>=-1 && x1(k)<= 1
x(k)=x1(k)
else x1(k)>1
x(k)=1
end
end
Sorry, didn't realize I didn't have the "code" option selected, should be easier to read now. The problem you are getting is because you are currently trying to make x(k)=x1, but x1 is currently a vector, and you only need the corresponding element x1(k).
Hope this helps.
  2 Commenti
sagar pokhrel
sagar pokhrel il 17 Set 2014
I used same for x and y and ran the code but it just gave me single output instead of length (x1)( 730). How do i run code for each 830 x and corresponding Y to get 830 output
Thanks in advance
Saagar
Saagar il 17 Set 2014
any chance that you could post the code you used? it would make it easier to follow what you are asking

Accedi per commentare.

Più risposte (0)

Categorie

Scopri di più su Dialog Boxes in Help Center e File Exchange

Tag

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by