Matrix dimensions must agree
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Hi:
Im trying to develop a generalized jacobian for a free space manipulator. Im using the following code:
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
phi0 = 0.25*pi; phi1 = 0.25*pi; phi2 = 0.25*pi;
m0 = 1100; m1 = 25; m2 = 25;
a1 = 0.5; a2 = 0.5;
b0 = 0.5; b1 = 0.5; b2 = 0.5;
l0 = 0.5; l1 = 0.5; l2 = 0.5;
w = m0 + m1 + m2;
M0 = m0*(m1+m2)/w; M1 = m0*m2/w; M2 = (m0 + m1)*m2/w;
I0 = [(1100*2)/12 0 0;0 (1100*2)/12 0;0 0 (1100*2)/12]; I1 = [0.0267 0 0;0 0.3467 0;0 0 2.5]; I2 = [0.0267 0 0;0 0.3467 0;0 0 2.5];
h0 = I0 + M0*b0^2; h1 = I1 + M0*a1^2 + M2*b1^2 + 2*M1*a1*b1; h2 = I2 + M2*a2^2;
hc1 = (M0*b0*a1 + M1*b0*b1)*cos(phi1); hc2 = (M1*a1*a2 + M2*b1*a2)*cos(phi2); hc3 = M1*b0*a2*cos(phi1 + phi2);
Ka = (m0*b0/l0)/w; Kb = (m0 + m1*b1/l1)/w; Kc = (m0 + m1 + m2*b2/l2)/w;
IM1 = h1 + h2 + hc1+ 2*hc2 + hc3; IM2 = h2 + hc2 + hc3; IS = h0 + h1 + h2 + 2*hc1 + 2*hc2 + 2*hc3;
s0 = sin(phi0); s1 = sin(phi0 + phi1); s2 = sin(phi0 + phi1 + phi2); c0 = cos(phi0); c1 = cos(phi0 + phi1); c2 = cos(phi0 + phi1 + phi2);
JM = [-l1*s1 -l2*s2; l1*c1 l2*c2]*[Kb 0; Kc Kc] - [-Ka*l0*s0 - Kb*l1*s1 - Kc*l2*s2; Ka*l0*c0 + Kb*l1*c1 + Kc*l2*c2]*[IM1/IS IM2/IS]; %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
As per the consulted documentation, the term [IM1/IS IM2/IS] should be a 2X1 matrix so it result in a 2X2 matrix when multiplied by the term [-Ka*l0*s0 - Kb*l1*s1 - Kc*l2*s2; Ka*l0*c0 + Kb*l1*c1 + Kc*l2*c2] that is a 1X2 matrix.
What does the "/" simbol means in order to get such result???
Thank you in advance!
2 Commenti
Geoff Hayes
il 31 Ago 2014
Soko - if you step through the code, you will notice that IM1 and *IM2 are 3x3 matrices. As are, IM1/IS IM2/IS. The result, [IM1/IS IM2/IS], is a 3x6 matrix. Hence the error. What documentation are you consulting?
Risposte (1)
Star Strider
il 31 Ago 2014
2 Commenti
Star Strider
il 31 Ago 2014
If you break JM apart, the problem shows itself:
JM1 = [-l1*s1 -l2*s2; l1*c1 l2*c2]*[Kb 0; Kc Kc];%
JM2 = - [-Ka*l0*s0 - Kb*l1*s1 - Kc*l2*s2; Ka*l0*c0 + Kb*l1*c1 + Kc*l2*c2];
JM3 = [IM1/IS IM2/IS];
JM1 is (2x2), JM2 is (2x1) but JM3 is (3x6). Also, IM1, IM2, and IS are all (3x3).
I’ll let you sort out whatever the problem is with IM1, IM2, and IS being (3x3) rather than (2x2) that you want them to be.
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